2007-12-06 12:11:35 · 4 answers · asked by Guy 3 in Science & Mathematics ➔ Mathematics
There is no absolute value of the square root of 7 because it isnt an even number.
Sorry but that's the truth!
2007-12-06 12:16:59 · answer #1 · answered by Michelle 3 · 0⤊ 0⤋
Given a complex number x+yi, the absolute value is defined as â(x² + y²).
In your problem, x=2 and y=â7, so the absolute value is
â(2²+(â7)²)
=â(4+7)
=â(11)
=3.32, approximately
But...why? Are you familiar with the geometrical interpretation of complex numbers? If so, then the absolute value of a complex number is simply its distance from the origin in the complex plane. Just like the absolute value of a real number is its distance from the origin on the real number line.
Thus, using the Pythagorean Theorem, the absolute value of x+yi is sqrt of (x² + y²).
Cheers!
Nicholas
2007-12-06 12:20:56 · answer #2 · answered by Anonymous · 0⤊ 0⤋
abs val is â[2² + (â7)²] = â(4 + 49) = â53
2007-12-06 12:18:00 · answer #3 · answered by Philo 7 · 0⤊ 0⤋
Holy smokes!! I thought 8th grade was bad. What grade are you in?
2007-12-06 12:14:11 · answer #4 · answered by ? 4 · 0⤊ 0⤋