Math question?

Question

Can you show me how you do it?

Find two consecutive odd integers whose sum is 116

Find two consecutive even integers whose sum is 126

Find three consecutive odd integers whose sum is 117

Answer 1

first one:
x= first integer
x + 2 = second integer

x+x+2 = 116
2x+2= 116
2-2x+2= 116-2
2x/ 2= 114/2
x= 57

THEREFORE
x= first integer = 57
x + 2 = second integer = 59
57+59 = 116

Answer 2

57 + 59 = 116. If the integers are consecutive AND odd they have to be 2 numbers apart. I divided 116 by 2 which was 58, subtracted one to get the odd number 57 and added two to that to get the odd number 59.

126 ^ 2 = 63
62 + 64 = 124

117 ^ 3 = 39
37 + 39 + 41 = 117

There's probably a nice formula, but common sense seemed to work just fine.

Answer 3

let x= 1st integer
let x+2= 2nd integer (Since the next odd integer will be 2 numbers away ex. 3+2=5, the next odd integer

x+x+2=116
2x+2=116
-2 -2
2x=114
--- ------
2 2
x=57
x+2=59

Try the rest on your own. I hope this helps