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The solution set is what?

2007-12-06 09:43:17 · 12 answers · asked by Anonymous in Science & Mathematics Mathematics

12 answers

7x + 28 = 9x - 18
46 = 2x
x = 23

2007-12-08 03:27:34 · answer #1 · answered by Como 7 · 2 0

First, element x^4 + 9x^2 + 8 x^4 + 9x^2 + 8 = (x^2 + 8) * (x^2 + a million) So: (Ax + B) / (x^2 + 8) + (Cx + D) / (x^2 + a million) = (15x^2 + 7x + sixty 4) / (x^4 + 9x^2 + 8) (Ax + B) * (x^2 + a million) + (Cx + D) * (x^2 + 8) = 15x^2 + 7x + sixty 4 Ax^3 + Ax + Bx^2 + B + Cx^3 + 8Cx + Dx^2 + 8D = 15x^2 + 7x + sixty 4 Ax^3 + Cx^3 = 0x^3 Bx^2 + Dx^2 = 15x^2 Ax + 8Cx = 7x B + 8D = sixty 4 A + C = 0 B + D = 15 A + 8C = 7 B + 8D = sixty 4 A + 8C - A - C = 7 - 0 7C = 7 C = a million A + C = 0 A + a million = 0 A = -a million B + 8D - B - D = sixty 4 - 15 7D = 40 9 D = 7 B + D = 15 B = 8 we've: (-x + 8) * dx / (x^2 + 8) + (x + 7) * dx / (x^2 + a million) wreck it aside: 8 * dx / (8 + x^2) - x * dx / (x^2 + 8) + x * dx / (a million + x^2) + 7 * dx / (a million + x^2) combine each and each term: 8 * dx / (8 + x^2) 8 + x^2 = 8 + 8 * tan(t)^2 x^2 = 8 * tan(t)^2 x = 2 * sqrt(2) * tan(t) dx = 2 * sqrt(2) * sec(t)^2 * dt 8 * 2 * sqrt(2) * sec(t)^2 * dt / (8 + 8 * tan(t)^2) => 8 * 2 * sqrt(2) * sec(t)^2 * dt / (8 * sec(t)^2) => 2 * sqrt(2) * dt combine 2 * sqrt(2) * t => 2 * sqrt(2) * arctan(x / (2 * sqrt(2))) x * dx / (8 + x^2) u = 8 + x^2 du = 2x * dx (a million/2) * du / u combine (a million/2) * ln|u| => (a million/2) * ln|8 + x^2| x * dx / (a million + x^2) u = a million + x^2 du = 2x * dx (a million/2) * du / u combine (a million/2) * ln|u| => (a million/2) * ln|a million + x^2| 7 * dx / (a million + x^2) x = tan(t) dx = sec(t)^2 * dt 7 * sec(t)^2 * dt / (a million + tan(t)^2) => 7 * sec(t)^2 * dt / sec(t)^2 => 7 * dt combine 7t + C => 7 * arctan(x) + C positioned all of them jointly: 2 * sqrt(2) * arctan(x / (2 * sqrt(2))) - (a million/2) * ln|8 + x^2| + (a million/2) * ln|a million + x^2| + 7 * arctan(x) + C you are able to simplify further, yet there is the indispensable.

2016-11-13 21:45:04 · answer #2 · answered by ? 4 · 0 0

Distribute the 7 and the 9, then solve for x.
7x + 28 = 9x -18
2x = 46
x = 23

2007-12-06 09:49:33 · answer #3 · answered by Anonymous · 0 1

(:

7(x+4) = 9(x-2)
[Distributive Property]
7x + 28 = 9x - 18
[Subtract 7x from the left and add 18 from the right]
46 = 2x
[Divide]
x = 23

(:

2007-12-06 09:53:26 · answer #4 · answered by Ashley 3 · 0 0

Simplifying
7(x + 4) = 9(x + -2)

Reorder the terms:
7(4 + x) = 9(x + -2)
(4 * 7 + x * 7) = 9(x + -2)
(28 + 7x) = 9(x + -2)

Reorder the terms:
28 + 7x = 9(-2 + x)
28 + 7x = (-2 * 9 + x * 9)
28 + 7x = (-18 + 9x)

Solving
28 + 7x = -18 + 9x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-9x' to each side of the equation.
28 + 7x + -9x = -18 + 9x + -9x

Combine like terms: 7x + -9x = -2x
28 + -2x = -18 + 9x + -9x

Combine like terms: 9x + -9x = 0
28 + -2x = -18 + 0
28 + -2x = -18

Add '-28' to each side of the equation.
28 + -28 + -2x = -18 + -28

Combine like terms: 28 + -28 = 0
0 + -2x = -18 + -28
-2x = -18 + -28

Combine like terms: -18 + -28 = -46
-2x = -46

Divide each side by '-2'.
x = 23

Simplifying
x = 23

2007-12-06 09:51:51 · answer #5 · answered by Anonymous · 0 2

7(x+4)=9(x-2)
7x+28 = 9x-18
7x - 9x = -18 - 28
-2x = -46
x = 23

2007-12-06 09:54:11 · answer #6 · answered by TT 4 · 0 0

distribute. 7x+28=9x-18 Subtract 7x
28=2x-18 Add 18
46=2x Divide by2
23=x

2007-12-06 09:49:54 · answer #7 · answered by Sahil 3 · 0 1

x = 23

2007-12-06 09:48:26 · answer #8 · answered by trumpski 2 · 0 1

7x + 28 = 9x - 18
46=2x
x=23

check
7(27)=9(21)
189 =189

2007-12-06 09:51:09 · answer #9 · answered by confused human 1 · 0 1

7(x+4)=9(x-2)
7x+28=9x-18
-7x -7x
28=2x-18
+18 +18
46=2x

2007-12-06 09:51:22 · answer #10 · answered by arik 1 · 0 1

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