2007-12-06 09:07:44 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
6√3 because 108 = 9 * 12 = 3*3*3*2*2
2007-12-06 09:10:31 · answer #1 · answered by Jim L 3 · 0⤊ 0⤋
Square Root Of 108
2016-11-02 09:00:15 · answer #2 · answered by Anonymous · 0⤊ 0⤋
108=9*4*3
the root =3*2*root3
=6*root of 3
2007-12-06 09:18:06 · answer #3 · answered by Maro 1 · 0⤊ 0⤋
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First, let's break the 2 numbers down to factors, 48=2x2x2x2x3 108=2x2x3x3x3 Whenever you have a pair of the same factor, you can take both of them of the the square root, and when then come out, only one left. For example, 2x2 inside will be 2 outside. so sr(48) = sr (2x2x2x2x3) 2 pairs of 2 comes out sr(48) = 2x2 sr(3) same goes for sr (108) = 2x3 sr (3) so now the whole equation becomes this 2x2 sr(3) + 2x3 sr (3) or 4 sr (3) + 6 sr (3) now, we notice that both terms contain a common factor "sr(3)" so Let's factor him out sr (3) (4+6) so 10 times square root of 3 is your answer Hope that hels! :)
2016-03-27 06:47:26 · answer #4 · answered by Anonymous · 0⤊ 0⤋
sqrt 108= sqrt of 36 * sqrt 3= 6 sqrt 3
2007-12-06 09:13:27 · answer #5 · answered by Dave aka Spider Monkey 7 · 1⤊ 0⤋
36*3 = 108
sqrt(36) = 6
now you're left with
6 * sqrt(3)
2007-12-06 09:12:40 · answer #6 · answered by Kewee 1 · 0⤊ 0⤋
sqrt(108) = sqrt[3(2^2)(3^3)] = 6sqrt(3)
2007-12-06 09:11:23 · answer #7 · answered by Anonymous · 0⤊ 0⤋
sq rt (108) = sq rt (9 *12)
sq rt (9) = 3
sq rt (12) = sq rt (4*3)
sq rt (4) = 2
Putting it all together, sq rt (9*12) = 3*2*(sq rt 3) = 6*(sq rt 3)
2007-12-06 09:14:27 · answer #8 · answered by Jennifer S 2 · 2⤊ 0⤋