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3 answers

In one hour, that's

3.83 x 10^26W (1J/1W.s)(3600s) = 1.3788 x 10^30 Joules

E = mc^2

m = E/c^2

m = 1.3788x10^30J / (299,792,458 m/s)(299,792,458 m/s)(1J/1kg.m^2/s^2)

m = 1.534 x 10^13 kg

2007-12-06 09:38:58 · answer #1 · answered by Anonymous · 0 0

The good and very smart Dr Grayce explains it here:

http://www.newton.dep.anl.gov/askasci/ast99/ast99441.htm

Apparently, its only about 4 million metric tons per sec.

He** if I lost that much I would have them abbs all the youngens is a huntin fur!

2007-12-06 09:39:12 · answer #2 · answered by Anonymous · 0 0

This is the worlds most famous equation.

E=-mc^2

m=E/c^2

Watts is Joules (energy) per second. x 60 is joules per hour. You know E, you know c, solving will get you the mass lost in an hour.

2007-12-06 09:18:31 · answer #3 · answered by Phoenix Quill 7 · 0 0

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