Calculate the standard entropy change for the combustion of methanol at 25 °C.?

Question

Calculate the standard entropy change for the combustion of methanol at 25 °C.

2 CH3OH(λ) + 3 O2(g) → 2 CO2(g) + 4 H2O(g)

Species S° (J/K⋅mol)
CH 3 OH (λ) 127.2
O 2 (g) 205.1
CO 2 (g) 213.7
H 2 O(g) 188.8

a.-312.9 J/K
b.+70.2 J/K
c.+2052.3 J/K
d.-2052.3 J/K
e.+312.9 J/K

Answer 1

DeltaS = DeltaS(Products) - DeltaS(Reactants).
DeltaS = [2(213.7) + 4(188.8)] - [ 2(127.2) + 3(205.1)]
DeltaS = [427.4 + 755.2] - [254.4 + 615.3]
DeltaS = 1182.6 - 869.7
DeltaS = 312.9 JK^-1

'e' is the correct answer.