w/46 = 70%/100%
w = 70% x 46 / 100% = 32.2
So you were able to type 32.2 words per minute to gain 70%
2007-12-06 06:56:15
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answer #1
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answered by lenpol7 7
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the problem is misleading since if 60% is 30 wpm then the 100% must be 50 wpm not 46. also if 100% is 46 then the 60% must be 27.6 wpm. then the proportionality is non linear.
you need to mention which type of curves does the relatoin follow. here i suggest linear two slope relation;
for those who pass this grade is starting at 30 wpm and assigning it a 60%.also it ends with 46 wpm and assigning it 100% .so for any grade more than 60% subtract 60% from it. also subtract 60% from 100% to get 40% also subtract 30 from 30 to get 0 wpm at 60% (now 0%) and 30 from 46 to get 16 for 100% (now 40%). add 30 to the result because it is now offset to 30 wpm.
this solution suggests that the proptinality is linear and the slope from 30 to 46 wpm is not the same of that from 0 to 30 wpm
the proportionality will be then
60%=0% ----- 30=0 wpm
100%=40% ----- 46=16 wpm
70%=10% ----- x wpm
or x=16*0.1/0.4=4
the real score =30+4=34 wpm
2007-12-06 15:57:17
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answer #2
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answered by an ugly mind 2
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Hey can you figure what is the exact info ?? is 46 words per min 100% or 30 words per min is 60%
bcos if 46 words per min is 100% then 70% is 32.2 wpm
if 30 words per min is 60% then 100% is 50 words and 70% is 35 wpm
2007-12-06 15:02:59
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answer #3
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answered by harsha_kadi 2
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Not enough information.
1. No question actually asked.
2. If you want to know how many words per minute you typed, you will need to include how many words per minute a passing grade is.
3. If you want to know how many words per minute a passing grade is, you will need to include how many words per minute you typed.
The equations would go like this... if we let 'p' be how many words per minute a passing grade is and 't' be how many words per minute you typed. We can find how many words per minute you type with the following equation:
11.5+p(0.75)=t
We can find how many words per minute a passing grade is with the following equation:
(t-11.5)/0.75=p
Update:
Well that just made it a lot easier now that you told me that 60% is 30 words per minute. Now you have two points you make a line find the equation of the line and then find other points on the line. Points are...
(100,46) and (60,30)
so slope is
(46-30)/(100-60)=16/40=2/5
2/5x+b=y plug in 100 and 46 to solve for b
2/5(100)+b=46
40+b=46
b=6
So the equation of your line is...
2/5x+6=y
Now put in 70 for x
2/5*70+6=34 You got 34 words per minute. Let's check this with my other equation above.
11.5+p(0.75)=t
11.5+(30)(0.75)=34
Yep everything matches. I would have been severely disappointed if it had not.
Final point... The other people that answered this are assuming that 0 words per minute is 0% this is not the case. We can easily see from the equation that if you didn't make 6 words per minute you are getting a 0% which is more than fair in my opinion.
2007-12-06 15:15:25
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answer #4
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answered by zenock 4
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I assume you want to know how fast a 70% and 60% student can type, so....
y = 46 * .7
y = 32.2 --> So you typed at 32 words per minute
p = 46 * .6
p = 27.6 --> So a passing speed is 28 words per minute
2007-12-06 14:55:16
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answer #5
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answered by Zandia 3
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you got 70% of 46 wpm which is 32.2 words per minute
passing is 60% of 46 wpm which is 27.6 words per minute
2007-12-06 14:53:05
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answer #6
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answered by RickSus R 5
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46 * .7 = 32.2
you got 32.2 per minute.
2007-12-06 14:54:05
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answer #7
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answered by CatNip 6
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I think this is right but I'm not sure but I think you got 32.2 words per minute.
2007-12-06 15:00:53
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answer #8
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answered by Anonymous
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0.7 * 46 = 32.2 wpm
2007-12-06 14:52:41
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answer #9
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answered by beer drinkers 2
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