2007-12-06 03:43:38 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
P( A ∩ B ) = P(A) + P(B) - P(A U B)
P( A ∩ B ) = 0.8 + 0.7 - 0.9
P( A ∩ B ) = 0.6
2007-12-06 10:12:40 · answer #1 · answered by Como 7 · 2⤊ 0⤋
P(AorB) = P(A)+ P(A) - P(AandB) =.90
=> P(AandB) = P(A)+ P(A)- 0.90
=> P(AandB) = .8 + .7 - .9
= Ans
2007-12-06 11:50:24 · answer #2 · answered by harry m 6 · 0⤊ 0⤋
P(A orB) = P(A) + P(B) - P(A and B)
.90 = .80 + .70 - P(A and B)
.90 - .80 - .70 = -P(A and B)
-.60 = -P(A and B)
.60 = P(A and B)
2007-12-06 11:51:55 · answer #3 · answered by Linda K 5 · 1⤊ 0⤋
P(A orB) = P(A) + P(B) - P(A and B)
.90 = .80 + .70 - P(A and B)
.90 - .80 - .70 = -P(A and B)
-.60 = -P(A and B)
.60 = P(A and B)
2007-12-06 12:07:51 · answer #4 · answered by Anonymous · 0⤊ 1⤋
Everything Harry says, but the answer is 0.6. He subtracted wrong!
2007-12-06 11:52:24 · answer #5 · answered by Anonymous · 1⤊ 0⤋
I used a Venn diagram.
P(Aand B) = 0.6
P(A and not B) + P(B and not A) + P(Aand B) = 0.9
P(A) = P(A and B) + P(A and not B)
P(B) = P(A and B ) + P(not A and B)
2007-12-06 11:51:09 · answer #6 · answered by Hiker 4 · 0⤊ 0⤋