I know this has somthing to do with what x is going to equal to get zero but i still dont get it.
Solve: x^2-5x+6=0
a. x= 2, x= 3 c. x= 1, x= 6
b. x= -2, x= -3 d. x= -1, x= 6
2007-12-06 02:14:58 · 10 answers · asked by soulof_adragon89 1 in Science & Mathematics ➔ Mathematics
a) x = 2, x = 3
Factor: (x-2)*(x-3) = x2 - 5x + 6 = 0
X - 2 = 0, x = 2
x - 3 = 0, x = 3
2007-12-06 02:20:07 · answer #1 · answered by WT 4 · 2⤊ 0⤋
First factor x^2-5x+6=0.
After factoring it will look like this:
(x-3)(x-2)=0
this means that either (x-3) or (x-2) MUST equal 0 in order for the equation to make sense.
so x has to be either 3 or 2 b/c (3-3) = 0 and (2-2) = 0.
2007-12-06 02:21:40 · answer #2 · answered by Anonymous · 1⤊ 0⤋
x² - 5x + 6 can be factored into (x-6)(x+1).
Since (x-6)(x+1) = 0, either (x-6) = 0 or (x+1) = 0, or both.
They gave you four pairs of possible values for x. Test each pair to see if (x-6) = 0 or (x+1) = 0.
2007-12-06 02:21:05 · answer #3 · answered by DWRead 7 · 0⤊ 0⤋
Factor the equation to (x-2)(x-3)=0
Set each factor to 0.
x-2=0, x=2
x-3=0, x=3
2007-12-06 02:20:11 · answer #4 · answered by oaksctp 2 · 1⤊ 0⤋
First factor x^2-5x+6=0. After factoring it is going to look like this: (x-3)(x-2)=0 this implies that the two (x-3) or (x-2) might opt to equivalent 0 to verify that the equation to make journey. so x ought to be the two 3 or 2 b/c (3-3) = 0 and (2-2) = 0.
2016-10-19 09:43:54 · answer #5 · answered by henshaw 4 · 0⤊ 0⤋
a) x = 2, x = 3
Factor: (x-2)*(x-3) = x2 - 5x + 6 = 0
X - 2 = 0, x = 2
x - 3 = 0, x = 3
2007-12-06 02:34:48 · answer #6 · answered by Anonymous · 1⤊ 0⤋
you're just supposed to insert the X=number into your equation and then you have to solve it.
2007-12-06 02:20:07 · answer #7 · answered by Eva K 3 · 0⤊ 1⤋
It's not nonsense.
2007-12-06 02:32:33 · answer #8 · answered by Michael M 7 · 0⤊ 1⤋
use a scientific calculator. its easy
2007-12-06 02:18:36 · answer #9 · answered by Q 2 · 0⤊ 1⤋
your answer is 'a'
2007-12-06 02:29:25 · answer #10 · answered by stringsdepotplus 2 · 0⤊ 1⤋