the x-2 is over the x^2-4 i know ive seen this before but cant remember to save my life.
2007-12-06 01:52:10 · 9 answers · asked by soulof_adragon89 1 in Science & Mathematics ➔ Mathematics
forgot to add i need to simplify it.
2007-12-06 01:56:38 · update #1
(x - 2) / (x - 2)(x + 2) = 1 / (x + 2)
2007-12-08 02:55:49 · answer #1 · answered by Como 7 · 2⤊ 0⤋
Factor denominator
x-2/(x-2)(x+2)
1/x+2
2007-12-06 09:57:49 · answer #2 · answered by oaksctp 2 · 0⤊ 0⤋
First you need a question! You probably want to put the fraction in simplest form -- that is, reduce it to lowest terms.
How do you reduce 10/15? First factor it into
5*2 / 5*3 and since 5/5 = 1 you can "cancel" 5/5 to get 2/3.
Work your problem the same way. First factor the x^2-4, and notice that you can write the x-2 as (x-2)*1. Then cancel the common factors.
2007-12-06 09:58:04 · answer #3 · answered by baja_tom 4 · 0⤊ 0⤋
x-2/(x-2)(x+2)=1/(x+2)
2007-12-06 09:56:54 · answer #4 · answered by someone else 7 · 0⤊ 0⤋
x-2*2/x
2007-12-06 09:55:44 · answer #5 · answered by goingcrazy!! 1 · 0⤊ 1⤋
You can factor any number a^2 - b as (a+b)(a-b).
This is what you have in the denominator so factor it.
x^2 - 4 = (x-2)(x+2)
As you can see, you have one of those terms in the numerator, (x-2).
So you can cancel them. Now you have 1/(x+2) as your answer.
2007-12-06 10:06:58 · answer #6 · answered by cornz000 1 · 0⤊ 0⤋
-1/x-2
here
x-2/x^2-4
same base, subtract the exponent.
* which is 1-2 = -1 = x^-1
2007-12-06 10:34:30 · answer #7 · answered by Anonymous · 0⤊ 0⤋
mathweb.com will give you the answer to this question and many more check them out i use them alot teachers hate this site.
2007-12-06 09:55:53 · answer #8 · answered by Anonymous · 0⤊ 1⤋
[04]
(x-2)/(x^2-4)
=(x-2)/{(x)^2-(2)^2}
=(x-2)/(x+2)(x-2)
=1/(x+2)
2007-12-06 10:01:03 · answer #9 · answered by alpha 7 · 0⤊ 0⤋