Can someone plz help I have to use the quadratic formula to solve 1/8x^2 + x + 5/2 = 0?

Answer 1

(1/8)x^2 + x + (5/2) = 0

You could do the quadratic formula as it's written, but it would be easier if you first got rid of those fractions.

Multiply everything by 8...
x^2 + 8x + 20 = 0

a = 1
b = 8
c = 20

x = [-b +- sqrt (b^2 - 4ac)] / 2a
= [-8 +- sqrt (8^2 - 4*1*20)] / 2*1
= [-8 +- sqrt (64 - 80)] / 2
= [-8 +- sqrt (-16)] / 2
= [-8 +- 4i] / 2
= -4 +- 2i

***********
Here's how, using the fractions:

a = 1/8
b = 1
c = 5/2

x = [-b +- sqrt (b^2 - 4ac)] / 2a
= [-1 +- sqrt (1^2 - 4*1/8*5/2)] / 2(1/8)
= [-1 +- sqrt (1 - 5/4)] / (1/4)
= [-1 +- sqrt (-1/4)] * (4/1)
= [-1 +- i(1/2)] * (4/1)
= -4 +- 2i

Answer 2

this problem can not be solved with real roots.....
the roots(or solutions) will be imaginary, i.e. in the form of i(the square root of -1).

solution:
step 1:
multiply the equation with 8 on both sides, we get
x^2+8x+20=0
step 2:
use the determinant formula of quadratic equations
x= [-8+-[sqrt{64-4(1)(20)}]] /2
step 3:
the solutions are imaginary and are as follows

-4+2i and -4-2i

Answer 3

multiply everythingby 8
x^2+8x+20=0
x=-8+-sqrt-16 all over 2
=-4+-2i

Answer 4

x² + 8x + 20 = 0
x = [- 8 ± √(64 - 80) ] / 2
x = [- 8 ± √ (- 16 )] / 2
x = [- 8 ± 4i ] / 2
x = - 4 ± 2i

Answer 5

you have 2 answers:

x=-4+2i, -4-2i