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A mixture of contain 76.5% NaCl , 6.5% MgCl2 , and 17.0% Na2S04 by mass. What is morality of Cl- ions in a solution formed by dissolving 7.50g of mixture in enough water to form 500.0ml of solution

2007-12-06 01:30:56 · 2 answers · asked by Anonymous in Science & Mathematics Chemistry

2 answers

In each 1 gram of the solid mixture, you have 0.765 grams NaCl and 0.065 grams of MgCl2.

Divide each of those masses by the molar mass of the compound to give you the moles of each compound/gram of the mixture. Multiply those numbers of moles by 7.5 to give you the number of moles of each compound in 7.5 grams of the mixture.

Each mole of NaCl produces 1 chloride ion, but each mole of CaCl2 gives 2 moles of chloride ions, so multiply the moles of CaCl2 by 2. Add the moles of chloride ions from NaCl + moles of chloride from CaCl2 to get the total moles of chloride ions.

Finally, divide that number of moles by 0.5 L to give you the final molarity.

2007-12-06 01:37:07 · answer #1 · answered by hcbiochem 7 · 0 0

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2016-12-17 09:07:24 · answer #2 · answered by ? 4 · 0 0

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