A flask containing 155 cm3 of hydrogen was collected unser a pressure of 22.5 kPa. What pressure would have been required for the volumne of gas to have been 90.0 cm3, assuming the same temperature.
2007-12-06 00:45:55 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
iman is way off and probably showing his age :-)
The way to solve this is p1*v1 = p2*v2
This assumes the temperature and the mass are the same. Finishing the calculation gives a result of 38.75 kPa which is rounded to 38.8 kPa (needs to have three significant figures).
This answer makes sense because you have collected the same amount of gas in a smaller container so the pressure has to be larger than 22.5 kPa. Always double check your answers with logic and common sense!
good luck!
2007-12-06 06:52:47 · answer #1 · answered by Rush is a band 7 · 0⤊ 0⤋
in my country this is high school standard question...(4 ur in4 mation)
do u know the formula for the gas law??
pv=t,p= pressure, t=temperature, v=volume
in this case t is the constant
so the equaion become like this
p=tv, where t is constant
22.5=t(155)
t=0.145
if the new volume is 90.0,
p=(0.145)(90.0)
p=13.0645 kPa
can i know ur age?
2007-12-06 09:16:53 · answer #2 · answered by iman 2 · 0⤊ 1⤋