the answer says "y=+/- (root3) times x" but i can't get that answer. 10 points for the first right answer, thanks!
2007-12-06 00:31:02 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x = r cos t ( t for theta)
y -= r sin t
by divsion
y = x tan t
now sec t = 2
sec^2 t = 4
tan ^2 t = sec^2 t- 1 = 3
tan t = +/-root(3)
so y = +/-root(3) x
2007-12-06 01:42:24 · answer #1 · answered by Mein Hoon Na 7 · 0⤊ 1⤋
secθ=2
cos θ = 1/2
cos^2 θ = 1/4
sin^2 θ = 3/4
y^2/x^2 = (sin^2 θ)/(cos^2 θ) = (3/4)/(1/4) = 3
so y^2 = 3 x^2 or "y=+/- (root3) times x"
2007-12-06 08:44:27 · answer #2 · answered by ben e 7 · 1⤊ 0⤋
sec a =2
1/cos =2
cosa=1/2
a=2kp+or -60
2007-12-06 08:41:52 · answer #3 · answered by Anonymous · 1⤊ 1⤋
1 / cos θ = 2
cos θ = 1 / 2
θ = 60 ° , 300° (1st and 4th quadrants)
x = cos 60° = 1/2
y = sin 60° = â3
y = sin 300° = - â3
x = cos 300° = 1/2
x = 1/2 , y = 屉3
2007-12-06 09:38:23 · answer #4 · answered by Como 7 · 1⤊ 2⤋
my answer is the same as with ben...
2007-12-06 08:47:22 · answer #5 · answered by rAvEn JoHn 2 · 1⤊ 0⤋