1) Prove that 1/n * sin x = 6
2) Given that
lim 1/(x-8) = ∞
x→8
calculate
lim 1/(x-3)
x→3
2007-12-06 00:20:47 · 9 answers · asked by Dr D 7 in Science & Mathematics ➔ Mathematics
1. cancel the n's
2. w (or m)
2007-12-06 00:46:06 · answer #1 · answered by _asv_ 3 · 5⤊ 2⤋
1/n *Sin x = 6
cancel " n"
Si x = 6 lol thats something i did in my school days LMAO
lim 1/(x-8 ) = â
substitute 8 in place of x u get
lim 1/0 which indeed is equal to â
and
lim 1/(x-3)
again when u put the value of x u get
lim 1/ (3-3)
lim 1/0 = â
So u get ur answers now :D ;-)
2007-12-06 12:07:42 · answer #2 · answered by kittana 6 · 4⤊ 0⤋
Something is wrong with the first problem. Look again to see what you missed. Is this some sort of limit?
2)
lim 1/(x-8) = â
xâ8+
The limit as x approaches 8 from the right is indeed infinity, however if x approaches 8 from the left the limit is - â
You have the same problem as x approaches 3. In both cases the limit is â only if the denominator remains positive, which is the case when x approaches from the right.
2007-12-06 08:34:47 · answer #3 · answered by Peter m 5 · 2⤊ 2⤋
Very cute. I hate to admit it took me way too long to see
six = 6
And I finally see the 8 and 3 tipped over.
At least I didn't suffer as much as Lisa in that old Simpsons episode...
2007-12-06 09:18:36 · answer #4 · answered by Steve H 5 · 2⤊ 0⤋
Prove that 1/n * sin x = 6
Cancel the n's
(sin x)/n = si x = 6
2007-12-06 08:27:02 · answer #5 · answered by ben e 7 · 6⤊ 2⤋
Those are cool. I was trying to decipher what n and sin and x were cos I'm that bad at math n I looked at the other answers.
im still kind of confused hahahaha but i get the first one. i think
2007-12-06 10:01:14 · answer #6 · answered by o0♥0o 1 · 0⤊ 1⤋
Out of some crazy box
2007-12-06 08:25:46 · answer #7 · answered by Anonymous · 0⤊ 1⤋
(sin x)/n = si x = 6
i think?
2007-12-06 10:33:59 · answer #8 · answered by Joe Reed 2 · 0⤊ 0⤋
??????
2007-12-06 08:24:10 · answer #9 · answered by Anonymous · 0⤊ 1⤋