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Solve for 0 ≤ Θ ≤ 2π
tan Θ = -3

I used a similar technique for a question: cos Θ = 1/4 but I couldn't match the books question, any suggestions?
thanks

2007-12-05 22:33:38 · 2 answers · asked by fye 1 in Science & Mathematics Mathematics

2 answers

tan θ = - 3
θ in 2nd and 4th quadrants.
θ = 108.4° , θ = 288.4°
or
θ = 1.89 radians , θ = 5.03 radians

2007-12-06 06:09:26 · answer #1 · answered by Como 7 · 2 0

Just find arctan(3), and add and subtract pi until you're past the boundaries you're given.

2007-12-06 06:38:28 · answer #2 · answered by Anonymous · 1 1

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