^ = square
2007-12-05 20:19:39 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(n-1)(n+1)
2007-12-05 20:22:24 · answer #1 · answered by Murtaza 6 · 1⤊ 0⤋
a² - b² = (a - b) (a + b)
n² - 1² = (n - 1) (n + 1)
2007-12-06 05:11:12 · answer #2 · answered by Como 7 · 1⤊ 0⤋
Simplifying
n^2 + -1
Reorder the terms:
-1 + n^2
Factor a difference between two squares.
(1 + n)(-1 + n)
Final result:
(1 + n)(-1 + n)
2007-12-06 06:26:36 · answer #3 · answered by Anonymous · 0⤊ 1⤋
the factor is actually x! = (x (x+1)) / 2
given that x = n^2-1 the formula turns to this:
x! = (n^2-1) * n^2 => x! = (n^4 - n^2) / 2
Long story short, (n^2-1) = (n^4 - n^2) / 2
To prove it... say we want to factor 6^2-1 (which equals to 35)
(6^2-1)! = (6^4 - 6^2) / 2 = 630 / 2 = 315 => (6^2-1)! = 315
now try to factor 35 and you will see 315 is the answer
:)
2007-12-06 04:50:43 · answer #4 · answered by mano_cornuto83 1 · 0⤊ 0⤋
yes (n+1)(n-1)
2007-12-06 04:28:23 · answer #5 · answered by chanty 2 · 1⤊ 0⤋
n^2-1
= (n+1)(n-1)
if we multply( n+1)*(n-1)
n^2-1n+1n-1
=1n-1n=0
therefor n^2-1 is the answer.
2007-12-06 04:30:22 · answer #6 · answered by ma b 5 · 1⤊ 0⤋
can you pick this as the best answer or ill KILL YOu lol please ill suck for 20 points and a fck or 50 points please please
2007-12-06 04:39:30 · answer #7 · answered by Anonymous · 1⤊ 2⤋