Please explain step by step how to solve.
Thanks
2007-12-05 18:33:24 · 7 answers · asked by Luke H 1 in Science & Mathematics ➔ Mathematics
Let x = the initial value of the rare coin
0.30x = the rise in the value of the rare coin
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x = 4500 - .30x
x + .30x = 4500
1.30x = 4500
x = 4500/1.30
x = 3,461.54 ===> initial value of the rare coin
.30x = .30 (3,461.54) = 1,038.46 ==> the rise in the value of the rare coin
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To check:
3,461.54 + 1,038.46 = 4,500
2007-12-05 18:49:23 · answer #1 · answered by detektibgapo 5 · 1⤊ 0⤋
Let the original price = x
From the question we get:
x + 30% of x = 4500
x + 3/10 x = 4500
13/10 x = 4500
x = 4500 * 10/13
x = 3461.54 (correct to 2 d.p)
2007-12-06 03:16:46 · answer #2 · answered by Anonymous · 0⤊ 0⤋
previous worth = $4500*100/130 = $3461.5385
2007-12-06 02:45:38 · answer #3 · answered by sv 7 · 0⤊ 0⤋
The answer is $3,461.54. You divide $4500 by 1.3
2007-12-06 03:56:14 · answer #4 · answered by Anonymous · 0⤊ 0⤋
130%<------->$4500
100%<-->(100 / 130) x $4500
$45000/13 = $3461.54
Was worth $3461.54
2007-12-06 09:52:07 · answer #5 · answered by Como 7 · 1⤊ 1⤋
4500=x+(x*30/100)
4500=(1+0.3)x
4500=(1.3)x
4500/1.3=x
3461.538=x the first value
2007-12-06 02:49:43 · answer #6 · answered by Rab 2 · 0⤊ 0⤋
$3461.54
4500/1.3 = 3461.54
100% of 3461.54 = 3461.54
30% of 3461.54 = 1038.46
Add the two to get 4500.00
2007-12-06 02:39:22 · answer #7 · answered by Kevin U 4 · 2⤊ 0⤋