log6(2x+5)=log6(2x+8)?

2 ⤊

log6(2x+5)=log6(2x+8)?

2007-12-05 18:18:49 · 4 answers · asked by Alexis O 1 in Science & Mathematics ➔ Mathematics

4 answers

unsolvable.
Remove the base :
2x + 5 = 2x + 8
0 = 3
Contradiction!
So, it is unsolvable for x.

2007-12-05 18:25:54 · answer #1 · answered by wangsacl 4 · 0⤊ 0⤋

im assuming its log base 6 so you could just set the two eq.'s = to each other

2x+5=2x+8

two logs with the same base can be set = to each other...goes for any number as the base...

2007-12-05 18:23:00 · answer #2 · answered by brian 2 · 0⤊ 0⤋

2x+5 = 2x+8
Move x's to one side and #s to other.
2x-2x=8-5
0 = 3

It doesn't work out. That is if it is Log BASE 6.

2007-12-05 18:29:06 · answer #3 · answered by Amanda 1 · 0⤊ 1⤋

Untrue!!!

2007-12-06 05:58:59 · answer #4 · answered by Como 7 · 2⤊ 0⤋