If the the space-time 'curvature' proposed by Relativity is real, wouldn't the curvature have to be through a higher dimension, since we can't see it? Think of the 2-dimensional grid diagram they use to illustrate gravity sometimes. Now extend that grid into 3 dimensions, creating a lattice. Now place a mass at the center of one of the cubes in that grid. What happens? The cube 'shrinks' a little, dragging the lines to the other cubes (spacetime) with it. That's the spacetime distorion (curvature) caused by gravity. If you think about that models of a tesseract you've seen, one cube inside the other, you see that gravity must be a 4th dimensional vector. It's relatively (!) easy to visualize if you think about it that way.
2007-12-05
18:12:36
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4 answers
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asked by
AmigaJoe
3
in
Science & Mathematics
➔ Physics
The 'Question' is about a 4th physical or spatial dimension, not time. Time can't be treated as a physical vector like the other dimensions.
2007-12-05
19:28:54 ·
update #1
"You don't need an extra dimension to warp a 3-dimensional spatial lattice. "
-You do if you want to warp space the way gravity does, normal to all other vectors, no?
2007-12-05
21:16:24 ·
update #2