A certain figure has and ares of 23 sq. cm. if the lengths of the sides are doubled, what will the area of the new figure be?
2007-12-05 17:57:44 · 5 answers · asked by megann, babyy 1 in Science & Mathematics ➔ Mathematics
Since we are dealing with area, when you multiply the length of the sides by x, the new area will be Ax^2. Since x = 2, the new area will be 23*4=92
2007-12-05 18:03:26 · answer #1 · answered by someone2841 3 · 1⤊ 0⤋
Area = 23 sq.cm.
Since you haven't stated the type of figure, it is assumed that the figure may be a square or rectangle since, it has mentioned length of the sides.
If a square, Area, A =s.s= 23 (!)
IFa rectangle, Area, A =lw (2)
If the sides are doubled, in (1):
A= 2s*s= 2(23)
Area = 46
IF a rectangle in(2):
A =(2l )(w) = 2X23
Area = 46 sq.cm.
2007-12-06 02:17:43 · answer #2 · answered by Anonymous · 0⤊ 0⤋
if that figure is a square, then the new figure should be 92 sq cm... the 2nd guy is right
2007-12-06 02:15:02 · answer #3 · answered by jor-jor 5 · 0⤊ 1⤋
No thanks.
I could Not even pass Pre-Algebra in college 2 years ago. lol
2007-12-06 02:04:43 · answer #4 · answered by SteverZ 3 · 0⤊ 0⤋
It should make the figure four times bigger.
2007-12-06 02:01:48 · answer #5 · answered by lisa b 3 · 1⤊ 0⤋