x^2 - 16 \ x + 4 = x - 4 / 3?

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2007-12-05 17:44:13 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

(x - 4) (x + 4) / (x + 4) = (x - 4) / 3
3 (x - 4)(x + 4) = (x - 4)(x + 4)
Error in question

2007-12-05 23:46:21 · answer #1 · answered by Como 7 · 2⤊ 1⤋

yes, only if x=4
factor x^2 - 16
cancle
*3 on both sides
factor out (x-4)
distribute
solve for x

2007-12-05 17:55:40 · answer #2 · answered by S K 2 · 1⤊ 1⤋

x^2-16/x+4=(x-4)*(x+4)/(x+4)=x-4
x-4 = (x-4)/3 ? *
eq. * is correct if only x-4=0 , x=4

2007-12-05 19:16:07 · answer #3 · answered by goodi 3 · 1⤊ 1⤋