Write the equilibrium constant for the following reactions CH3COOH +H2O AND 2NOCL?

Question

Please help with these chemsitry questions

Answer 1

first in writing equilibrium constant or k you should remeber the "golden rule" in writing it..here it goes:

k= [products] / [reactants]
always remember the brackets....this brackets represents the amount of concentrations of your reactants as well as products
if your data is right...and if my deduction is right...your reactants is CH3COOH and your product is 2NOCL...:) i hope im right...then your equilibrium constant should be

k = ([NOCL]^2) / [CH3COOH]

cool huh?...now you may ask what happened to your precious H2O...well in equilibria....water is always equals to unity or 1 so like in any other mathematical equations...when you mulitply any amount by 1 you would arrive with the number itself..so there i hope i answered your question...:)

Answer 2

you're on the right song. constantly placed the products interior the numerator and reactants interior the denominator, each and every enhance to the means of the coefficient that seems till now each and every substance interior the balanced equation. The exception is which you do not regularly comprise H2O in ok expressions, because of the fact the concentration of water is included into the ok fee. So, regularly depart out H2O (l) in ok expressions.