The problem reads: " For vector v = (-3,4), graph the vector, compute its magnitude and find the angle of the vector and the nearest x-axis.
I drew a picture and used a parallelogram to help solve for the magnitude and angle of the vector and the x-axis.
I got a magnitude of 5 for v and the angle of v and the x-axis is 53.1 degrees.
If anyone could check this over I would greatly appreciate it!
2007-12-05 16:48:16 · 4 answers · asked by No Doubt 1 in Science & Mathematics ➔ Mathematics
This vector form a 3,4,5 triangle with angles of 53.1 degrees and 36.9 degrees. You have it correct, but remember it because it is a classic and you will see it many times.
c^2 = 3^2 +4^2 = 9+16 = 25
sqrt25 = 5
cosx = 3/5 = .6
arccos(.6) = 53.1 degrees
2007-12-05 17:05:14 · answer #1 · answered by justforfun_1811 3 · 1⤊ 0⤋
Vector is r /_θ
Vector is 3 Left and 4 Up (2nd quadrant)
r ² = 3² + 4² = 25
r = 5
θ = (180 - tan^(-1) 4/3 °)
θ = 180 - 25.3 °
θ = 154.7°
r = 5 /_ 154.7°
2007-12-06 02:01:48 · answer #2 · answered by Como 7 · 1⤊ 1⤋
Thats it. Its a pythagorean triple. Good job!
2007-12-05 16:52:40 · answer #3 · answered by Anonymous · 1⤊ 1⤋
I got D to be <40.2, -49.5,0>, the magnitude is 63.8 @ 309.1 degrees
2016-05-28 09:49:02 · answer #4 · answered by Anonymous · 0⤊ 0⤋