physics? plz help, 10 pts?

Question

An inventor proposes to make a pendulum clock using a pendulum bob with mass m at the end of a thin wire of length L. Instead of swinging back and forth, the bob moves in a horizontal circle with constant speed v, with the wire making a constant angle beta with the vertical. Assuming that the time T for one revolution is known, find thetension F in the wire and angle beta. (derive the equation)

i honestly do not understand what this is asking me to do. And i do not understand how to solve without being given any values, any help is much appreciated.

i'm in grade 11, and this is not a book question, my teacher just gave us a worksheet he created, and i don't understand this problem because he never really explained it to us. But yes i agree with u i think it has something to do with centripetal acceleration because we're covering that right now.

Answer 1

The tension in the wire has two components, horizontal and vertical. The vertical component is equal to the weight of the mass, mg. The horizontal component must be sufficient to provide the necessary centripetal force to keep the mass moving in a circle

F_vertical = mg
F_horizontal = m v^2 / r

The velocity v = 2π / T ( one circumference per period )

The tension = sqrt ( F_vertical ^2 + F_horizontal ^2 )

The angle = inv-tan ( F_vertical / F_horizontal )

Answer 2

yo i think it has something to do with centripetal acceleration...those formulas check ur textbook theres formula that has like [4(pi)r^2]/t^2 im not sure but i think thats it (check it man) and you just isolate for t and for the angle, it's should be on the velocity so break it up into componets like vcosx and vsinx and ....it would help if there was numbers but anyways check the book and the sample question 1 or 2 or 3 they all show you how to maneuvre around the equation. Sounds like grade 12 physics good luck? whos the teacher?

Answer 3

T = 2(pi) (sqr rt(L/g))
The period of a pendulum is only dependent onthe square root of its length, not on its mas or amplitude.

For any maximum displacement less than 15 degrees, the motion of a pundulum is a simple harmonic motion; that is the force due to the gravity is proportional to its displacement.