two more word problems..............?

Question

the perimeter of a triangle is 82cm. the longest side is 13cm more than the shortest side. the medium side is 6 cm more than the shortest side. find the lengths of the sides.

and

the length of a rectangle is 11 inches longer than its width. the perimeter is 98 inches. find the length and width.

thankyou

lurv s

Answer 1

Triangle: Let s be the shortest side, s+6 the medium side, and s+13 the longest side. Put these all on the left side, and 82 on the right. Add up like terms, and solve for s.

Rectangle: Let w = width, w+11 the length. P = 2(l+w), substitute for the length, add, multiply, and solve for x.

Answer 2

1) Let "s" be the shortest side, since the other sides are given in terms of this. This means the longest side is s + 13, and the medium side is s + 6. The perimeter is the sum of all the sides, so s + (s+13) + (s+6) = 82. Solve this equation for s, and use "s" to write s, s+13, and s+6.

2) Use a similar approach here. Remember that opposite sides of a rectangle are the same length, and add up all four sides.

Answer 3

a = shortest side
b = medium
c = longest

a + b + c = 82
c= 13 + a (longest is 13 more than shortest)
b= 6 + a (medium is 6 more than shortest)
substitute both c and b into the top equation:
a + (6 + a) + (13 + a) = 82 -solve for a
a = 21
then plug a into the other two equations
b = 6 + (21) = 27
c = 13 + (21) = 34

your answers are:
shortest side: a=21
medium: b=27
longest: c=34

Problem 2:
follow the same procedure you did in the previous equation...

your not just putting your homwork problems on here so other ppl can do them for you & you can copy them are you? lol, its all good

Answer 4

let x = shortest side
(x+13) + (x+6) + x = 82
3x + 19 = 82
3x = 63
x = 21 cm
x + 6 = 27 cm
x + 13 = 24 cm

L = 11 + w
2L + 2w = 98
substitute 11 + w for L in the second equation
2(11 + w) + 2w = 98
22 + 4w = 98
4w = 120
w = 30 in
L = 41 in