A spherical snowball is melting in such a way that its diameter is decreasing at rate of 0.3 cm/min.?

Question

At what rate is the volume of the snowball decreasing when the diameter is 8 cm?

Answer 1

V=4/3(d/2)^3*pi=(1/6)d^3*pi

Vf-Vi = (1/6)8^3*pi - (1/6)(8-.03)^3*pi = 29.04cm^3/min

Answer 2

the volume of a sphere is: 4/3(pi)(d/2)^3

where d is the diameter

You have dd/dt = 0.3
(change of diameter with respect to change in time).
d = 8

Start from there and here's a hint: You are learning about derivatives right?

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