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which equation do you use? and are the planets radius's necessary.?
thanks a bunch!!!!

2007-12-05 14:17:50 · 7 answers · asked by chickloombaa 2 in Science & Mathematics Astronomy & Space

7 answers

yes

force of gravity = gravitational constant X (mass one x mass two)/radius of planet

2007-12-05 14:26:41 · answer #1 · answered by Anonymous · 0 1

You can rebuild the equation with two basic ones:

F = m * a, and
F = G * M * m / d^2

Where F is the force pulling on an object.
m is the mass of the object
M is the mass of the planet
d is the distance from the object to the centre of the planet (if you look for surface gravity, then this is the radius of the planet)
d^2 is the distance squared (or the radius squared)
G is a constant: 6.672 x 10^-11 N m^2 / kg^2 (to make the units come out right).

The first equation can be rewritten as
a = F/m (we are looking for the acceleration)

Therefore, rewrite the second equation:
F/m = G * M / d^2
and your get
a = G * M / d^2

(because the mass of the object cancels out, this means that the acceleration is the same for any object)

Mars has a mass of 6.42 x 10^23 kg
Mars has a radius of 3,396,000 m (at the equator)
(make sure to use the same units as in the constant)

a = (6.672 x 10^-11 N m^2 / kg^2)*(6.42 x 10^23 kg) / (3,396,000 m)^2
a = 3.712 N/kg

1 Newton is equivalent to 1 kg m / s^2
(It is defined as the force needed to give a 1 kg mass, an acceleration of 1 m/s^2)
the kg cancel out, leaving us with

a = 3.712 m/s^2

which is roughly 38% that of Earth.

---

For Jupiter, this is a little trickier, because there is not 'solid' surface. Astronomers use the top of the opaque part of the atmosphere (the clouds).

Mass = 1.9 x 10^27 kg
Equatorial radius = 71,490,000 m

use
a = G * M / d^2

(G is the same constant)

2007-12-05 14:34:24 · answer #2 · answered by Raymond 7 · 2 0

Formula For Acceleration Of Gravity

2016-11-08 03:19:23 · answer #3 · answered by Anonymous · 0 0

The formula is F = G (m1xm2)/r^2
where
F = the gravitational force
G = the gravitational constant (approximately 6.67 x 10^-11 N m^2 kg^2)
m1 = the mass of the object on the surface (in kg)
m2 = the mass of the planet (in kg)
r = the radius of the planet (in meters)

2007-12-05 14:29:29 · answer #4 · answered by Anonymous · 0 0

This Site Might Help You.

RE:
How do you find the acceleration of gravity on the surface of Mars and Jupiter?
which equation do you use? and are the planets radius's necessary.?
thanks a bunch!!!!

2015-08-13 01:18:44 · answer #5 · answered by Shawn 1 · 0 0

For the best answers, search on this site https://shorturl.im/awcve

I've provided the answer (example) for 'Phobos' in your question. Now you use the formula g = GM/r^2 for the other bodies. If you designate values for Earth as M` & r` then g`(Earth) = GM`/r`^2; Then g/g` = [M/M`] / [r/r`]^2. this will give the ratio of accelerations due to gravity, given the mass ratio & ratio of radii. Do your home work.

2016-04-02 07:51:34 · answer #6 · answered by Anonymous · 0 0

Taking Earth's Gravity as 9.18 m/s2 Mars = 3.84 m/s2 Venus = 8.91 m/s2 Jupiter = 24.85 m/s2 Europa = 1.26 m/s2 Phobos = 5.09 x 10^-3 m/s2 The formula is as poorna kumar used not that i knew but i just gave the numbers.

2016-03-16 22:10:18 · answer #7 · answered by Anonymous · 0 0

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