I have a quick question. We just finished boat races and I need to calcuate the bouyant force "exerted onto your boat by the water" as well as the "volume of water displaced by your boat."
We know that 1kg=1liter of water and 1 gallon=8.35lbs of water.
If you can please show me how (math-wise) I would appreciate it. I want to understand it too if I may ask, the answer is just a number but knowing how to calcuate it out is half the struggle. =)
2007-12-05 13:53:04 · 1 answers · asked by Greg J 2 in Science & Mathematics ➔ Physics
As the boat is being placed into the water it displaces a volume V of water. The displaced water is trying to push the boat out of the water with a buoyant force Fb. This buoyant force is
Fb=gpV
g- acceleration due to gravity (9.81 m/s^2)
p - density of water (1000 kg/m^3)
V - volume of water displaced. (in m^3)
Example. Given an empty steel container that is by volume 50% submerged in water. Its dimentions are 40x 40x50 cm.
What is the buoyant force?
V= 0.4 x0.4 x0.5=0.08 m^3
sice only 50% is submerged
V= 0.5 x 0.08=.04m^3
Fb=g p V
Fb= 9.81 x 1000 x 0.04=392 N
2007-12-05 14:08:23 · answer #1 · answered by Edward 7 · 1⤊ 0⤋