A gas originally at 27 °C and 1.00 atm pressure in a 3.9 L flask is cooled at constant pressure until the temperature is 11 °C. The new volume of the gas is __________ L.
2007-12-05 13:26:46 · 3 answers · asked by gregmmercer 1 in Science & Mathematics ➔ Chemistry
You can use Amonton's Law to answer this question.
Because the pressure is constant, we are monitoring the changes in temperature and volume.
Therefore, we must use the equation T1/V1 = T2/V2. Plug in your givens, and you should get 300.K/3.9L=284K/V2. Solving for V2 you get 3.7 L.
2007-12-05 13:31:36 · answer #1 · answered by Anonymous · 5⤊ 0⤋
You can use the formula P1V1/Ti = P2V2/T2; solving for V2:
V2 = P1V1T2/T1P2 =
1.00atm x 3.9L x 284K/300K x 1.00atm = 3.7 liters
2007-12-05 13:34:24 · answer #2 · answered by Flying Dragon 7 · 4⤊ 0⤋
P1V1 = P2V2
-------- = ----------
T1 ===== T2
combined gas law
Celsius must be converted to kelvin (add 273 to the celsius)
try it and you should come up with your correct answer
(answer is 4.119 L)
2007-12-05 13:33:43 · answer #3 · answered by Anonymous · 0⤊ 3⤋