What is the greatest possible values of these integers?
2007-12-05 12:35:39 · 18 answers · asked by Maddy505 1 in Science & Mathematics ➔ Mathematics
a-1+a+a+1<= 16
3a=<16
a-1 = 4
a = 5
a+1 = 6
2007-12-05 12:39:45 · answer #1 · answered by toffee357 2 · 0⤊ 0⤋
the greatest possible value of these integers are 4, 5, then 6 because 4 plus 5 plus 6 equalls 15. There are no other whole numbers greater than these that if you add consecutively will be less than or equal to 16.
2007-12-05 20:40:37 · answer #2 · answered by Anonymous · 0⤊ 0⤋
4 5 and 6 is 15
2007-12-05 20:39:11 · answer #3 · answered by Anonymous · 1⤊ 0⤋
If consecutive means in order then 4,5,& 6. 4+5=9+6=16
2007-12-05 20:40:00 · answer #4 · answered by N'S@NE 3 · 0⤊ 0⤋
4,5,6 4+5=9+6=15
15
2007-12-05 20:38:40 · answer #5 · answered by 3daysgrace 2 · 1⤊ 0⤋
4+5+6 = 15
5+6+7 = 18
So 4-6 is correct
2007-12-05 20:38:27 · answer #6 · answered by Jonathan J 2 · 1⤊ 0⤋
well, write an example- 1, 2, 3
now, write a "let statement"
n=the first number, n+1= second number, n+2= third number.
each small formula represents how you got from one number to the next.
now make an equation:
n+n+1+n+2=16
combine like terms:
3n+3=16
SOLVE
-subtract 3 from both sides (3n=13)
-divide by three
13/3=n
NOW u use your let statements from above to find your three values!!
13/3, 14/3, 15/3 YAY =P
ok, i have to add: was it suppose to be a whole number?
2007-12-05 20:44:09 · answer #7 · answered by Anonymous · 0⤊ 0⤋
456
2007-12-05 21:31:23 · answer #8 · answered by Anonymous · 0⤊ 0⤋
Well, 4+5+6 is 15.
5+6+7 is 18, too big.
2007-12-05 20:39:05 · answer #9 · answered by Computer Guy 7 · 1⤊ 0⤋
4,5,6 equals 15
2007-12-05 20:39:23 · answer #10 · answered by dg2003 5 · 0⤊ 0⤋