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find the rectangular form of 4(cos5/6pi)+i sin(5/6pi)), and find the trigonometric form of( sqrt3) -i?

no calculators please

2007-12-05 12:19:06 · 1 answers · asked by chrys 1 in Science & Mathematics ➔ Mathematics

1 answers

cos 5pi/6=-cospi/6=1/2 sqrt3
sin5pi/6 = sin pi/6 =1/2
so 2sqrt3+i*1/2
b)modulus= sqrt(3+1) =2
tan@=-1/sqrt3 =-1/3sqrt3
so @=-pi/6 and the trigonometric form is 2<-pi/6

2007-12-05 12:57:46 · answer #1 · answered by santmann2002 7 · 0⤊ 0⤋

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