math question please show work dont come here if ur not going to give the answer with work and mess around.?

Question

1. Mrs. hunt runs a child care facility in her home. she is currently watching two children, Chase Kim and Kerry Oh.
Mrs. Kim picks up Chase late about 20% of the time and Mr. Oh picks up Kerry late about 30% of the time. on any day, what is the probability that both children will be picked on time?

2. what is the probability that both children will be picked up late?

please show work and state the final answer clearly

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Answer 1

Probability ( Mrs. Kim is late ) = 0.20 (20%)
Probability ( Mrs. Kim is on time ) = 1 - 0.20 = 0.80 (80%)

Probability ( Mr. Oh is late ) = 0.30 (30%)
Probability ( Mr. Oh is on time ) = 1 - 0.30 = 0.70 (70%)

PROBLEM 1:

Probability both are picked up on time. This is simply the product of the probabilities:

In general, with two independent events A and B.

P(A and B) = P(A) * P(B)

Therefore:
P( K on time ) * P ( O on time ) = 0.80 x 0.70 = 0.56 (56%)

The probability that *both* children will be picked up *on time* is:
56%

PROBLEM 2:

Probability both are picked up late. Same method, just use the probabilities of being late.

P( K is late ) * P ( O is late ) = 0.20 x 0.30 = 0.06 (6%)

The probability that *both* children will be picked up *late* is:
6%

P.S.

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:-)