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At 7:00 Joe starts jogging at 6mph. At 7:10 Ken starts off after him. How fast must Ken run in order to overtake Joe at 7:30? The teacher uses a chart. We know D doesn't matter. We know time for Joe is 1/2hr and for Ken is 1/3hr. We do not know what formula to use for rate for each of them to figure d=r x t. Thank you!

2007-12-05 09:37:02 · 3 answers · asked by imok42day2003 1 in Science & Mathematics Mathematics

3 answers

Joe travels 3 miles
Ken must travel 3 miles in 20 min
i.e. 9 miles in 1 hour
Ken`s speed = 9 miles / h

2007-12-05 10:08:36 · answer #1 · answered by Como 7 · 2 2

So you have the formula

d=r x t

Let's say Joe's rate is r1, and time is t1. And Ken's rate is r2 and time is t2. So we know their distance will be the same at 7:30, right.

So we have

r1 x t1 = r2 x t2

Plugin the numbers:

6mph x (1/2) hour = r2 x (1/3) hour

If you solve the equation:

3 = r2 x (1/3)
3 * 3 = r2
9 mph = r2

2007-12-05 10:12:33 · answer #2 · answered by Freddy27 2 · 0 2

Distance = velocity x time t = time on parkway 6 - t = time on 2-lane 360 = 62t + fifty 4(6 - t) 360 = 62t + 324 - 54t 360 = 324 + 8t 36 = 8t 36/8 = 9/2 = t so use that to respond to the question

2016-10-10 08:29:41 · answer #3 · answered by ? 4 · 0 0

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