Stoichiometry?

Question

How many grams of phosphorus react with 55.2 L O2 at STP to form tetraphosphorus decaoxide?
P4(s) + 5O2(g) → P4O10(s)

Answer 1

(55.2 L)(32 g/22.4L ≈ 78.85714 g
x/(4*30.97) = (78.85714 g)/(10*16)
x = (78.85714 g)(4*30.97)/(10*16)
x ≈ 61.05514 g ≈ 61.1 g