ideal gas in chemistry?

Question

What is the mass of a 364.0 mL sample of ammonia gas at 10.6oC and 144.76 kPa?

Answer 1

Using the Ideal Gas Equation PV = nRT
P = Pressure /pascals 144.76 kPa
V = volume/m^3 364.0 /10^6
n = moles of gas to be found
R = The gas constant 8.31
T = temperature in Kelvin 283.6K

n = PV/RT
n = [144760 x 3.64 x 10^-4] / [8.31 x 283.6]
n = 0.022358502 moles

Mr(Ammonia ) = 17
Mass(NH3) = 17 x 0.022358502 = 0.38009g
mass(NH3) = 0.38g (2 d.p.)