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How do you complete the square with y^2-2y=8x-1?

2007-12-05 07:51:36 · 2 answers · asked by hottiechck7 1 in Science & Mathematics ➔ Mathematics

2 answers

y^2-2y=8x-1

y^2 - 2y + 1 = 8x - 1 + 1

(y - 1)^2 = 8x

2007-12-05 07:57:04 · answer #1 · answered by ben e 7 · 1⤊ 0⤋

y^2 - 2y + 1 = 8x -1 + 1
(y-1)^2 = 8x

2007-12-05 07:56:21 · answer #2 · answered by norman 7 · 2⤊ 0⤋

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