can u show me how to do this problem??

Question

1. dy/dx=______
y=(2x–1)^8 –x + e

So i've tried everything, but for some reason i keep getting the wrong answer :( can u help?

Answer 1

I guess that should be:

dy/dx
= 8(2)(2x-1)^7 - 1
=16(2x-1)^7 - 1

What did you get?

Answer 2

Chain rule
d
---( g(f(x)) ) = g'(f(x))f '(x)

dx

y' = d/dx ( (2x-1)^8 ) - d/dx(x)+ d/dx(e)

d/dx (x)=1
d/dx(e)= 0 since e is a number, not a variable.

Chain rule
g'=x^8

f'=2 (d/dx of 2x-1)

8(2x-1)^7(2)

Put together

16(2x-1)^7 - 1 Is that right?

Answer 3

y = (2x-1)^8 - x + e
dy/dx = 2x8(2x-1)^7 - 1
dy/dx = 16(2x - 1)^7 - 1

Answer 4

y=(2x–1)^8 –x + e

y' = [(2x-1)^8]' + (-x)' + (e)'
=8(2x-1)'[(2x-1)^7] - 1 + 0
=16[(2x-1)^7] - 1