What is the empirical formula of lactic acid?

Question

I've written down CH3CH(OH)COOH but I dunno if it's right

Also, what can you see when a colourless solution containing silver ions is tested with a solution containing chloride ions.
And what observation (if any) can you see when excess of aqueous ammonia is added to the mixture above.

Answer 1

You wrote the correct structural formula of lactic acid. The empirical formula is CH2O.

Ag+ + Cl- ===> AgCl(s) white precipitate of insoluble silver chloride.

AgCl(s) + 2NH3 ===> Ag(NH3)2+ + Cl- the white precipitate dissolves.

Answer 2

Don't know about the lactic acid. But the silver ions are going to react with the chloride ions and precipitate. When you add the ammonia it will bind to the cloride ions, replacing the silver, and the silver will deposit on the glass beaker or flask.

Answer 3

anticipate you have a one hundred gram pattern. 40.00 grams C 6.seventy one grams H fifty 3.29 O 40.0 grams a million mole/12.01 grams = 3.331 moles 6.seventy one grams a million mole/a million.01 grams = 6.644 moles fifty 3.29 grams a million mole/sixteen.00 = 3.331 C1H2O1 (the numbers are meant to be subscripts) 12 + 2.02 + sixteen = 30.02 grams for the empirical formula ninety/30.02 = 3 So we could desire to multiply the empirical formula by potential of three to get to the molecular formula C3H6O3 Tah dah. To the above poster: the factor is to not use Google, yet to apply the coolest judgment of Chemistry to experimentally determine a formula. This the fashion of thinking potential it is important to any scientist interior the lab, even with occupation.