Factor as follows:
(3y + 5)(y - 2) = 0
Therefore:
3y + 5 = 0
or
y - 2 = 0
y = -5/3
or
y = 2
2007-12-05 06:34:12
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answer #1
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answered by Puzzling 7
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Do by factoring,
3y^2 - y - 10 = (3y+5)(y-2) = 0
Solving 3y+5 = 0 and y-2 = 0 gives,
y = -5/3, 2
2007-12-05 06:33:29
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answer #2
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answered by sahsjing 7
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Simplifying
3y^2 + -1y + -10 = 0
Reorder the terms:
-10 + -1y + 3y^2 = 0
Solving
-10 + -1y + 3y^2 = 0
Solving for variable 'y'.
Factor a trinomial.
(-5 + -3y)(2 + -1y) = 0
Subproblem 1
Set the factor '(-5 + -3y)' equal to zero and attempt to solve:
Simplifying
-5 + -3y = 0
Solving
-5 + -3y = 0
Move all terms containing y to the left, all other terms to the right.
Add '5' to each side of the equation.
-5 + 5 + -3y = 0 + 5
Combine like terms: -5 + 5 = 0
0 + -3y = 0 + 5
-3y = 0 + 5
Combine like terms: 0 + 5 = 5
-3y = 5
Divide each side by '-3'.
y = -1.666666667
Simplifying
y = -1.666666667
Subproblem 2
Set the factor '(2 + -1y)' equal to zero and attempt to solve:
Simplifying
2 + -1y = 0
Solving
2 + -1y = 0
Move all terms containing y to the left, all other terms to the right.
Add '-2' to each side of the equation.
2 + -2 + -1y = 0 + -2
Combine like terms: 2 + -2 = 0
0 + -1y = 0 + -2
-1y = 0 + -2
Combine like terms: 0 + -2 = -2
-1y = -2
Divide each side by '-1'.
y = 2
Simplifying
y = 2
Solution
y = {-1.666666667, 2}
2007-12-05 07:54:25
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answer #3
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answered by Anonymous
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Factor it:
(3Y+5)(Y-2) = 0
For that to be true, either 3y+5 = 0 or y-2 = 0. You can solve those two pretty easily, I think.
2007-12-05 06:35:29
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answer #4
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answered by Judy 7
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(3y + 5) (y - 2) = 0
2007-12-05 06:33:10
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answer #5
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answered by Bill W 【ツ】 6
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y(3y-1)=10
2007-12-05 06:33:32
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answer #6
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answered by Ricky B 2
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y=2
3(2^2)-2-10=0
3(4)-2-10=0
12-2-10=0 ??
YES
the people who are showing you the factoring method are more correct than I am :)
Therefore y=2
2007-12-05 06:34:28
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answer #7
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answered by Anonymous
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(3y-5)(y+2)=0
y=-5/3,or
y=2
2007-12-05 06:53:01
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answer #8
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answered by sassycate 1
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