chem exam help....?

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a steel cylinder contains 128g of oxygen (O2) at 25`C and a pressure of 1000 torr. At STP 1 mol of a gas occupies 22.4 L what is the volume in liters of the oxygen gas in the cylinder??

2007-12-05 05:30:42 · 1 answers · asked by onehotmama 2 in Science & Mathematics ➔ Chemistry

1 answers

PV = nRT T=298K n = 128gO2 x 1molO2/32gO2 = 8 moles

V = nRT/P

V = (8moles)(62.4L-torr/k-mol) (298K) / (1000torr) = 149 L to three significant figures.

2007-12-05 06:08:30 · answer #1 · answered by steve_geo1 7 · 0⤊ 0⤋