Chemical equations?
Algebraic ones?
Well...if this is what you mean I am not sure it is in the right catorgary, but oh well. For both you just have to make both sides equal...
For example:
If : 3a+17=5a-2
You work it out using the rules of BID MAS...except, in rearranging the swap it around, just to confuse us, so SAM DIB (Subtraction, Addition, Multiplication, Division, Indicies, Brackets)
We will look at the minus first. If we wanted to get rid of -2...we will have to +2. Because in rearranging equation you ALWAYS DO THE SAME TO EACH SIDE, we must plus 2 to both sides. So...
3a+13+2=5a
3a+15=5a
We can then minus 3a from both side...following?
15=5a
To find out what a is, we must divide by 5...to BOTH sides.
3=a
Hope this helps you.
2007-12-05 05:15:55
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answer #1
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answered by Anonymous
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I get their physical weight exactly the same, then I set them equidistant from the fulcrum.
2007-12-05 05:24:08
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answer #2
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answered by NH_MCD 3
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