A certain sum of money consists of 440 coins some of which are 50 pence pieces and the rest are 10 pence pieces. If the total value of the coins is £60, find the number of 50 pence pieces
Help much appreciated!!!
Thanks!!
2007-12-05 03:14:22 · 2 answers · asked by Cookz 1 in Education & Reference ➔ Homework Help
x = number of 50 p coins
y = number of 10 p coins
x + y = 440
With two variables, a second formula is needed.
60 pounds = 6000 p
50x + 10y = 6000
y = 440 - x
50x + 10(440 - x) = 6000
50x + 4400 - 10x = 6000
40x = 1600
x = 40
2007-12-05 03:36:10 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Assuming 100 p to the pound
(it was 240 last time I was in England :)
Let L = the number of 50-pence pieces
Let X = the number of 10-pence pieces
X + L = 440
X ( 10 ) + L ( 50 ) = 6000
Use the first equation to isolate X
X = 440 - L
Then substitute into the second and solve for V
( 440 - L ) ( 10 ) + L ( 50 ) = 6000
4400 - 10 L + 50 L = 6000
40 L = 1600
L = 40
So there are 40 50-pence coins and 400 10-pence coins.
Check:
40 + 440 = 440 coins
40 * 50 + 400 * 10 = 2000 + 4000 = 6000 pence = 60 pounds.
2007-12-05 03:38:45 · answer #2 · answered by jgoulden 7 · 0⤊ 0⤋