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Question

You testify as an "expert witness" in a case involving an accident in which car A slid into the rear of car B, which was stopped at a red light along a road headed down a hill. You find that the slope of the hill is θ = 12.0°, that the cars were separated by distance d = 25.0 m when the driver of car A put the car into a slide (it lacked any automatic anti-brake-lock system), and that the speed of car A at the onset of braking was v0 = 16.0 m/s.

(a) With what speed did car A hit car B if the coefficient of kinetic friction was 0.60 (dry road surface)?
m/s

(b) What was the speed if the coefficient of kinetic friction was 0.10 (road surface covered with wet leaves)?
m/s

Answer 1

The starting KE is
.5*m*16^2
The gain in PE is
25*sin(12)*m*g

The force of friction in the skid is
m*g*cos(12)*µk

The general equation to find the speed at impact is
.5*m*v^2=.5*m*16^2+
25*sin(12)*m*g-25*m*g*cos(12)*µk

simplify
v^2=256+2*g*25*(sin(12)-cos(12)*µk)

a)µk=0.60
v=8.37

b)µk=0.10
v=17.61

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Answer 2

You reactants: a million Cl2 (g) 3 F2 (g) Your product: ClF3 Write out your chemical equation: Cl2 + 3F2 -----> ClF3 Now stability: Cl2 + 3F2 -----> 2ClF3 wish that facilitates.. good success! i know ways you sense on the subject of the internet task... i in my opinion do unlike them :)