plz help me solve...polynomial question
2007-12-05 02:34:02 · 7 answers · asked by shellyeph 1 in Science & Mathematics ➔ Mathematics
(3x-2)^2
9x^2-12x+4
if u have a right side we can solve it
for example if the right hand side is 0, then
(3x-2)^2=0
so
3x-2=0
3x=2
x=2/3
2007-12-05 02:38:53 · answer #1 · answered by Siva 5 · 0⤊ 0⤋
The answer is:
9X^2-12X+4
2007-12-05 10:52:26 · answer #2 · answered by Anonymous · 0⤊ 0⤋
what is this? expansion or extracting the roots?
if expansion it's 9x^2 -12x +4
if roots, it's 2/3 twice! since it's in the second degree
2007-12-05 10:38:58 · answer #3 · answered by gonpatrick21 3 · 0⤊ 0⤋
(3x - 2)^2
= (3x - 2) * (3x - 2)
= 3x (3x - 2) - 2(3x - 2)
= 3x*3x - 3x*2 - 2*3x -2(-2)
= 9x^2 - 6x - 6x + 4
= 9x^2 - 12x + 4
Hope that helps
2007-12-05 10:38:12 · answer #4 · answered by gmat g 3 · 0⤊ 0⤋
(3x-2)(3x-2)
9x^2 - 6x - 6x + 4
9x^2 - 12x + 4
2007-12-05 10:58:05 · answer #5 · answered by ~*BuBbLeTeA*~ 2 · 0⤊ 0⤋
(a-b)^2=a^2+b^2-2ab
(3x-2)^2=(3x)^2+(2^2)-(2*(3x)*2)
=9x^2+4-12x
=9x^2-12x+4
2007-12-05 10:40:20 · answer #6 · answered by Anonymous · 0⤊ 0⤋
9x² - 12x + 4
.
2007-12-05 10:37:20 · answer #7 · answered by Robert L 7 · 0⤊ 0⤋