sqrt of 63 minus 2 sqrt of 28 + 5 sqrt of 7.
2007-12-05 01:20:54 · 5 answers · asked by Kat 1 in Science & Mathematics ➔ Mathematics
√63 - 2√28 + 5√7
√(9*7) - 2√(4*7) + 5√7
3√7 - 4√7 + 5√7
4√7
.
2007-12-05 01:27:20 · answer #1 · answered by Robert L 7 · 1⤊ 1⤋
sqrt(63) - 2 sqrt(28) + 5 sqrt(7)
sqrt(7) sqrt(9) - 2 sqrt(7) sqrt(4) + 5 sqrt (7)
sqrt (7) [ 3 - 4 + 5 ]
4 sqrt(7)
2007-12-05 01:28:35 · answer #2 · answered by hznfrst 6 · 0⤊ 0⤋
you need to use surds
√63-2√28+5√7=
(√9x√7)-(2x√4x√7)+5√7=
3√7-4√7+5√7=
4√7
2007-12-05 01:27:38 · answer #3 · answered by Anonymous · 0⤊ 0⤋
guy, you should basically connect with me immediately message. i will help you by ability of all this. Math change into continuously my fantastic problem. a million. use the distributive resources with the first area (2) * (3a) - (2) * (-5) = 6a - (-10) or 6a+10 Now combine like words: 6a -4a = 2a so we are left with 2a +10 <------- do not decrease to rubble with the signs and indicators 2. Distribute the (-2t) to both parts of the binomial (t-5t^2) (-2t) * (t) + (-2t) * (-5t^2) undergo in concepts like signs and indicators yield a good effect and opposite ones a adverse, even as multiplying exponenets, you may upload the exponent numbers and (t) by ability of itself is like (t^a million), and do the mathematics on the numeral area and the variable area one at a time. so: -2t^2 + 10t^3 Now combine like words: (10t^3) + (-5t^3) = 5t^3 we are now left with: 5t^3 - 2t^2 <------- you should jot down it so as of reducing exponents.
2016-10-25 11:58:13 · answer #4 · answered by Anonymous · 0⤊ 0⤋
my answer is the same as the first one...
2007-12-05 01:48:29 · answer #5 · answered by rAvEn JoHn 2 · 0⤊ 1⤋