A very tall office building has 4 elevators and 60 floors. Each elevator travels upward at an average rate of 18 feet per second. There are 12 feet between floors in this building. Suppose you get on the elevator on the first floor and travel straight to the fifty-sixth floor without stopping. To the nearest second, how long will it take to travel from the first floor to the fifty-sixth floor on this elevator?
2007-12-05 01:08:39 · 12 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
37 and 1/3 seconds Ü
2007-12-05 01:13:38 · answer #1 · answered by Desqui 1 · 0⤊ 2⤋
Normally, people enter elevators on the ground floor. It would appear, from your question, that you lable this floor as the "first floor", placing you most probably in North America.
In Europe, the ground floor would have been labeled 0 (it is not a floor, it is the ground) and it is very rare that one gets an express elevator from a "non-ground" floor (e.g., the first floor) up to the top floors.
Therefore, there is a high probability that the story is located in North America, where superstitious beliefs abound: probably, there would be no 13th floor.
So looks like the elevator goes up 54 floors.
2007-12-05 09:33:28 · answer #2 · answered by Raymond 7 · 0⤊ 0⤋
There are 54 floors between these two floors. This will take 36 seconds to travel. Then it takes another 2/3 second to reach the 56th floor. So total time to the nearest second is 37 seconds.
55(12/18) = 36.67
2007-12-05 09:29:04 · answer #3 · answered by Don E Knows 6 · 0⤊ 0⤋
56 floor at 12 feet per floor = 672 feet
672 feet /18 feet per second = 37.33 seconds.
Normal rounding would be 37 seconds, but this would not get all the way to the 56th floor, so I'd say 38 seconds, with 2/3 seconds left over.
2007-12-05 09:27:20 · answer #4 · answered by LDJ 3 · 0⤊ 0⤋
The total distance from first floor to the ceiling of the 56th floor is
12 ft x 56 = 672 ft
Up to the ceiling of the 55th floor =
12 ft x 55 = 660 ft
Time to travel to the ceiling of 55th floor =
660 ft/ 18 ft/sec = 36.667 second
So by 37 seconds, you are already at 56th floor...
2007-12-05 09:19:21 · answer #5 · answered by detektibgapo 5 · 2⤊ 0⤋
37 seconds is travelling time (being inside the elevator).
plus 5 seconds waiting for the 1st elevator to take you up, answer is 42 seconds.
2007-12-06 21:27:53 · answer #6 · answered by Mugen is Strong 7 · 0⤊ 0⤋
The key to this is, how many floors does the elevator travel? (It is NOT 56.)
2007-12-05 09:16:29 · answer #7 · answered by genericman1998 5 · 2⤊ 0⤋
Find the distance from the first to the 56th = 12feet *55 (because you're starting on the first and don't count that) = 660feet
Now you can find the time using
rate = distance/time
18f/s = 660f/time
time = 36.67seconds
2007-12-05 09:20:28 · answer #8 · answered by Kris S 4 · 0⤊ 0⤋
37 seconds.
56 x 12 / 18 = 37.3333333 seconds
2007-12-05 09:17:15 · answer #9 · answered by gonpatrick21 3 · 0⤊ 2⤋
(56*12)/18=37.333333333333333333 sec
2007-12-05 09:54:03 · answer #10 · answered by rAvEn JoHn 2 · 0⤊ 0⤋