okay I get that you take the anti derivative and get 1/5e^5x but then I hit a wall
2007-12-03 18:57:52 · 4 answers · asked by clawedstar 1 in Science & Mathematics ➔ Mathematics
I = ∫ e^(5x) dx between 0 and 1
Let u = 5x
du = 5 dx
I = (1/5) ∫ e^u du between 0 and 5
I = (1/5) [ e^5 - e^0]
I = (1/5) [ e^5 - 1 ]
2007-12-03 20:20:37 · answer #1 · answered by Como 7 · 0⤊ 0⤋
integral(1-->0) e^5x dx = [(e^5x)/5](1-->0) = (1/5)[e^5x](1-->0)
= (1/5)(e^(5)(0) - e^(5)(1))
= (1/5)(e^0 - e^5)
= (1/5)(1 - e^5).
2007-12-03 19:07:28 · answer #2 · answered by Anonymous · 1⤊ 0⤋
You got the answer of integral already: (1/5)e^(5x)... let's continue
= (1/5)*[ e^(5*1)-e^(5*0)]
=1/5*[e^5 -1]...................since e^(0)=1
This is the answer you should've got
2007-12-03 19:04:27 · answer #3 · answered by Anonymous · 0⤊ 1⤋
then you go..
[1/5e^5(1)] -[1/5e^5(0)]
2007-12-03 19:03:20 · answer #4 · answered by sleepy 2 · 0⤊ 1⤋