what is the OH- concentration of a solution with a pH of 4.5?

7 ⤊

2007-12-03 18:14:23 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

First, find the pOH which is 14 - pH = 9.5

pOH = 9.5

By definition the [OH-] is 10^(-pOH) , so 10^(-9.5) = 3.16 x 10^-10 M.

Enjoy. =)

2007-12-03 18:33:52 · answer #1 · answered by officerbrother 2 · 4⤊ 0⤋

how did you go from 10^-9.5 to 3.16*10^-10 without a calculator?

2015-11-07 01:55:19 · answer #2 · answered by Anonymous · 0⤊ 0⤋

pH + pOH = 14
4.5 + pOh =14
pOH = 9.5
[OH] = 10^(-9.5)
[OH] = 3.16*10^(-8)

2007-12-03 19:01:59 · answer #3 · answered by Vishwas 1 · 2⤊ 0⤋

pH = log[H+]

pOH = 14 - log[H+]

pOH = 9.5

[OH] = 10^-9.5

[OH] = 3.16*10^-10

2007-12-03 18:33:37 · answer #4 · answered by gp4rts 7 · 1⤊ 1⤋