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Calculate the pH of a solution thats has a [OH-] = 1.5x10^-4 M?

2007-12-03 17:50:24 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

1 answers

pOH = log 1/[OH-]= log 1/1.510^-4 =log 6667=3.824

and pH=14-OH= 14-3.824=10.176

2007-12-03 17:57:00 · answer #1 · answered by maussy 7 · 1⤊ 0⤋

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